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Ajax如何传输Json和xml数据_AJAX相关_

2023-05-25 182人已围观

简介 Ajax如何传输Json和xml数据_AJAX相关_

ajax传输xml数据:只要把数据封装成xml格式就可以实现传输,前台js用responseXML接收xml参数,后台读取用流和dom4j来解析

前台页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>Ajax XML数据处理演示 Name: 
Age:


后台页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>Ajax XML数据处理演示 Name: 
Age:


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Ajax传输Json数据的要点利用Apache或者阿里巴巴的JSONArray类进行传输
前台代码

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>Ajax Json数据处理演示

JsonServlet1.java

 package cn.hncu.servlet; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; import java.util.List; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import cn.hncu.domain.User; public class JsonServlet1 extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doPost(request, response); } public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { //调用后台service.dao.query(),到数据库当中把信息读取出来 //为简化知识点的理解,此处后台部分的功能直接模拟 response.setContentType("text/html;charset=utf-8"); PrintWriter out = response.getWriter(); List users = new ArrayList(); users.add(new User("A001","Jack",20)); users.add(new User("A002","Rose",22)); users.add(new User("B001","张三",20)); users.add(new User("B002","李四",30)); String json=""; //用java封装出json格式的字符串:[{name:"Jack",age:25}, {...}, {...} ] for(User u:users){ if(json.equals("")){ json="{name:\""+u.getName()+"\",id:\""+u.getId()+"\",age:"+u.getAge()+"}"; }else{ json = json +",{ name:\""+u.getName()+"\",id:\""+u.getId()+"\",age:"+u.getAge()+"}" ; } } json="["+json+"]"; out.print(json); } } 

JsonServlet2.java

 package cn.hncu.servlet; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import cn.hncu.domain.User; import net.sf.json.JSONArray; import net.sf.json.JSONObject; public class JsonServlet2 extends HttpServlet { public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html;charset=utf-8"); PrintWriter out = response.getWriter(); List users = new ArrayList(); users.add(new User("A001","Jack",20)); users.add(new User("A002","Rose",22)); users.add(new User("B001","张三",20)); users.add(new User("B002","李四",30)); String strJson=com.alibaba.fastjson.JSONArray.toJSONString(users); System.out.println(strJson); //用fastjson工具(只有一个jar包)帮我们把list转换成json串 Map map = new HashMap(); map.put("addr", "湖南"); map.put("height", "170"); map.put("marry", "no"); map.put("user", new User("A003","小李",25)); String strMap=com.alibaba.fastjson.JSONArray.toJSONString(map); out.print(strMap.toStr
                
                

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